3.140 \(\int \frac {A+B \log (e (\frac {a+b x}{c+d x})^n)}{(a g+b g x)^2 (c i+d i x)} \, dx\)

Optimal. Leaf size=181 \[ -\frac {d \log \left (\frac {a+b x}{c+d x}\right ) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{g^2 i (b c-a d)^2}-\frac {b (c+d x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{g^2 i (a+b x) (b c-a d)^2}-\frac {b B n (c+d x)}{g^2 i (a+b x) (b c-a d)^2}+\frac {B d n \log ^2\left (\frac {a+b x}{c+d x}\right )}{2 g^2 i (b c-a d)^2} \]

[Out]

-b*B*n*(d*x+c)/(-a*d+b*c)^2/g^2/i/(b*x+a)-b*(d*x+c)*(A+B*ln(e*((b*x+a)/(d*x+c))^n))/(-a*d+b*c)^2/g^2/i/(b*x+a)
-d*(A+B*ln(e*((b*x+a)/(d*x+c))^n))*ln((b*x+a)/(d*x+c))/(-a*d+b*c)^2/g^2/i+1/2*B*d*n*ln((b*x+a)/(d*x+c))^2/(-a*
d+b*c)^2/g^2/i

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Rubi [C]  time = 0.69, antiderivative size = 455, normalized size of antiderivative = 2.51, number of steps used = 22, number of rules used = 11, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.256, Rules used = {2528, 2525, 12, 44, 2524, 2418, 2390, 2301, 2394, 2393, 2391} \[ -\frac {B d n \text {PolyLog}\left (2,-\frac {d (a+b x)}{b c-a d}\right )}{g^2 i (b c-a d)^2}-\frac {B d n \text {PolyLog}\left (2,\frac {b (c+d x)}{b c-a d}\right )}{g^2 i (b c-a d)^2}-\frac {d \log (a+b x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{g^2 i (b c-a d)^2}-\frac {B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A}{g^2 i (a+b x) (b c-a d)}+\frac {d \log (c+d x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{g^2 i (b c-a d)^2}-\frac {B n}{g^2 i (a+b x) (b c-a d)}+\frac {B d n \log ^2(a+b x)}{2 g^2 i (b c-a d)^2}+\frac {B d n \log ^2(c+d x)}{2 g^2 i (b c-a d)^2}-\frac {B d n \log (a+b x)}{g^2 i (b c-a d)^2}-\frac {B d n \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{g^2 i (b c-a d)^2}+\frac {B d n \log (c+d x)}{g^2 i (b c-a d)^2}-\frac {B d n \log (c+d x) \log \left (-\frac {d (a+b x)}{b c-a d}\right )}{g^2 i (b c-a d)^2} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*Log[e*((a + b*x)/(c + d*x))^n])/((a*g + b*g*x)^2*(c*i + d*i*x)),x]

[Out]

-((B*n)/((b*c - a*d)*g^2*i*(a + b*x))) - (B*d*n*Log[a + b*x])/((b*c - a*d)^2*g^2*i) + (B*d*n*Log[a + b*x]^2)/(
2*(b*c - a*d)^2*g^2*i) - (A + B*Log[e*((a + b*x)/(c + d*x))^n])/((b*c - a*d)*g^2*i*(a + b*x)) - (d*Log[a + b*x
]*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/((b*c - a*d)^2*g^2*i) + (B*d*n*Log[c + d*x])/((b*c - a*d)^2*g^2*i) -
(B*d*n*Log[-((d*(a + b*x))/(b*c - a*d))]*Log[c + d*x])/((b*c - a*d)^2*g^2*i) + (d*(A + B*Log[e*((a + b*x)/(c
+ d*x))^n])*Log[c + d*x])/((b*c - a*d)^2*g^2*i) + (B*d*n*Log[c + d*x]^2)/(2*(b*c - a*d)^2*g^2*i) - (B*d*n*Log[
a + b*x]*Log[(b*(c + d*x))/(b*c - a*d)])/((b*c - a*d)^2*g^2*i) - (B*d*n*PolyLog[2, -((d*(a + b*x))/(b*c - a*d)
)])/((b*c - a*d)^2*g^2*i) - (B*d*n*PolyLog[2, (b*(c + d*x))/(b*c - a*d)])/((b*c - a*d)^2*g^2*i)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rubi steps

\begin {align*} \int \frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{(140 c+140 d x) (a g+b g x)^2} \, dx &=\int \left (\frac {b \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d) g^2 (a+b x)^2}-\frac {b d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2 (a+b x)}+\frac {d^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2 (c+d x)}\right ) \, dx\\ &=-\frac {(b d) \int \frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{a+b x} \, dx}{140 (b c-a d)^2 g^2}+\frac {d^2 \int \frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{c+d x} \, dx}{140 (b c-a d)^2 g^2}+\frac {b \int \frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{(a+b x)^2} \, dx}{140 (b c-a d) g^2}\\ &=-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {(B d n) \int \frac {(c+d x) \left (-\frac {d (a+b x)}{(c+d x)^2}+\frac {b}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{140 (b c-a d)^2 g^2}-\frac {(B d n) \int \frac {(c+d x) \left (-\frac {d (a+b x)}{(c+d x)^2}+\frac {b}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{140 (b c-a d)^2 g^2}+\frac {(B n) \int \frac {b c-a d}{(a+b x)^2 (c+d x)} \, dx}{140 (b c-a d) g^2}\\ &=-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {(B n) \int \frac {1}{(a+b x)^2 (c+d x)} \, dx}{140 g^2}+\frac {(B d n) \int \left (\frac {b \log (a+b x)}{a+b x}-\frac {d \log (a+b x)}{c+d x}\right ) \, dx}{140 (b c-a d)^2 g^2}-\frac {(B d n) \int \left (\frac {b \log (c+d x)}{a+b x}-\frac {d \log (c+d x)}{c+d x}\right ) \, dx}{140 (b c-a d)^2 g^2}\\ &=-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {(B n) \int \left (\frac {b}{(b c-a d) (a+b x)^2}-\frac {b d}{(b c-a d)^2 (a+b x)}+\frac {d^2}{(b c-a d)^2 (c+d x)}\right ) \, dx}{140 g^2}+\frac {(b B d n) \int \frac {\log (a+b x)}{a+b x} \, dx}{140 (b c-a d)^2 g^2}-\frac {(b B d n) \int \frac {\log (c+d x)}{a+b x} \, dx}{140 (b c-a d)^2 g^2}-\frac {\left (B d^2 n\right ) \int \frac {\log (a+b x)}{c+d x} \, dx}{140 (b c-a d)^2 g^2}+\frac {\left (B d^2 n\right ) \int \frac {\log (c+d x)}{c+d x} \, dx}{140 (b c-a d)^2 g^2}\\ &=-\frac {B n}{140 (b c-a d) g^2 (a+b x)}-\frac {B d n \log (a+b x)}{140 (b c-a d)^2 g^2}-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {B d n \log (c+d x)}{140 (b c-a d)^2 g^2}-\frac {B d n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}-\frac {B d n \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{140 (b c-a d)^2 g^2}+\frac {(B d n) \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,a+b x\right )}{140 (b c-a d)^2 g^2}+\frac {(B d n) \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,c+d x\right )}{140 (b c-a d)^2 g^2}+\frac {(b B d n) \int \frac {\log \left (\frac {b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{140 (b c-a d)^2 g^2}+\frac {\left (B d^2 n\right ) \int \frac {\log \left (\frac {d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{140 (b c-a d)^2 g^2}\\ &=-\frac {B n}{140 (b c-a d) g^2 (a+b x)}-\frac {B d n \log (a+b x)}{140 (b c-a d)^2 g^2}+\frac {B d n \log ^2(a+b x)}{280 (b c-a d)^2 g^2}-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {B d n \log (c+d x)}{140 (b c-a d)^2 g^2}-\frac {B d n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {B d n \log ^2(c+d x)}{280 (b c-a d)^2 g^2}-\frac {B d n \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{140 (b c-a d)^2 g^2}+\frac {(B d n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{140 (b c-a d)^2 g^2}+\frac {(B d n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{140 (b c-a d)^2 g^2}\\ &=-\frac {B n}{140 (b c-a d) g^2 (a+b x)}-\frac {B d n \log (a+b x)}{140 (b c-a d)^2 g^2}+\frac {B d n \log ^2(a+b x)}{280 (b c-a d)^2 g^2}-\frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{140 (b c-a d) g^2 (a+b x)}-\frac {d \log (a+b x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{140 (b c-a d)^2 g^2}+\frac {B d n \log (c+d x)}{140 (b c-a d)^2 g^2}-\frac {B d n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {d \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (c+d x)}{140 (b c-a d)^2 g^2}+\frac {B d n \log ^2(c+d x)}{280 (b c-a d)^2 g^2}-\frac {B d n \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{140 (b c-a d)^2 g^2}-\frac {B d n \text {Li}_2\left (-\frac {d (a+b x)}{b c-a d}\right )}{140 (b c-a d)^2 g^2}-\frac {B d n \text {Li}_2\left (\frac {b (c+d x)}{b c-a d}\right )}{140 (b c-a d)^2 g^2}\\ \end {align*}

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Mathematica [C]  time = 0.29, size = 304, normalized size = 1.68 \[ -\frac {2 (b c-a d) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )+2 d (a+b x) \log (a+b x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )-2 d (a+b x) \log (c+d x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )-B d n (a+b x) \left (\log (a+b x) \left (\log (a+b x)-2 \log \left (\frac {b (c+d x)}{b c-a d}\right )\right )-2 \text {Li}_2\left (\frac {d (a+b x)}{a d-b c}\right )\right )+B d n (a+b x) \left (2 \text {Li}_2\left (\frac {b (c+d x)}{b c-a d}\right )+\log (c+d x) \left (2 \log \left (\frac {d (a+b x)}{a d-b c}\right )-\log (c+d x)\right )\right )+2 B n (-d (a+b x) \log (c+d x)+d (a+b x) \log (a+b x)-a d+b c)}{2 g^2 i (a+b x) (b c-a d)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*Log[e*((a + b*x)/(c + d*x))^n])/((a*g + b*g*x)^2*(c*i + d*i*x)),x]

[Out]

-1/2*(2*(b*c - a*d)*(A + B*Log[e*((a + b*x)/(c + d*x))^n]) + 2*d*(a + b*x)*Log[a + b*x]*(A + B*Log[e*((a + b*x
)/(c + d*x))^n]) - 2*d*(a + b*x)*(A + B*Log[e*((a + b*x)/(c + d*x))^n])*Log[c + d*x] + 2*B*n*(b*c - a*d + d*(a
+ b*x)*Log[a + b*x] - d*(a + b*x)*Log[c + d*x]) - B*d*n*(a + b*x)*(Log[a + b*x]*(Log[a + b*x] - 2*Log[(b*(c +
d*x))/(b*c - a*d)]) - 2*PolyLog[2, (d*(a + b*x))/(-(b*c) + a*d)]) + B*d*n*(a + b*x)*((2*Log[(d*(a + b*x))/(-(
b*c) + a*d)] - Log[c + d*x])*Log[c + d*x] + 2*PolyLog[2, (b*(c + d*x))/(b*c - a*d)]))/((b*c - a*d)^2*g^2*i*(a
+ b*x))

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fricas [A]  time = 0.77, size = 194, normalized size = 1.07 \[ -\frac {2 \, A b c - 2 \, A a d + {\left (B b d n x + B a d n\right )} \log \left (\frac {b x + a}{d x + c}\right )^{2} + 2 \, {\left (B b c - B a d\right )} n + 2 \, {\left (B b c - B a d + {\left (B b d x + B a d\right )} \log \left (\frac {b x + a}{d x + c}\right )\right )} \log \relax (e) + 2 \, {\left (B b c n + A a d + {\left (B b d n + A b d\right )} x\right )} \log \left (\frac {b x + a}{d x + c}\right )}{2 \, {\left ({\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} g^{2} i x + {\left (a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2}\right )} g^{2} i\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)^2/(d*i*x+c*i),x, algorithm="fricas")

[Out]

-1/2*(2*A*b*c - 2*A*a*d + (B*b*d*n*x + B*a*d*n)*log((b*x + a)/(d*x + c))^2 + 2*(B*b*c - B*a*d)*n + 2*(B*b*c -
B*a*d + (B*b*d*x + B*a*d)*log((b*x + a)/(d*x + c)))*log(e) + 2*(B*b*c*n + A*a*d + (B*b*d*n + A*b*d)*x)*log((b*
x + a)/(d*x + c)))/((b^3*c^2 - 2*a*b^2*c*d + a^2*b*d^2)*g^2*i*x + (a*b^2*c^2 - 2*a^2*b*c*d + a^3*d^2)*g^2*i)

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)^2/(d*i*x+c*i),x, algorithm="giac")

[Out]

Timed out

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maple [F]  time = 0.48, size = 0, normalized size = 0.00 \[ \int \frac {B \ln \left (e \left (\frac {b x +a}{d x +c}\right )^{n}\right )+A}{\left (b g x +a g \right )^{2} \left (d i x +c i \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*ln(e*((b*x+a)/(d*x+c))^n)+A)/(b*g*x+a*g)^2/(d*i*x+c*i),x)

[Out]

int((B*ln(e*((b*x+a)/(d*x+c))^n)+A)/(b*g*x+a*g)^2/(d*i*x+c*i),x)

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maxima [B]  time = 1.29, size = 427, normalized size = 2.36 \[ -B {\left (\frac {1}{{\left (b^{2} c - a b d\right )} g^{2} i x + {\left (a b c - a^{2} d\right )} g^{2} i} + \frac {d \log \left (b x + a\right )}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} g^{2} i} - \frac {d \log \left (d x + c\right )}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} g^{2} i}\right )} \log \left (e {\left (\frac {b x}{d x + c} + \frac {a}{d x + c}\right )}^{n}\right ) + \frac {{\left ({\left (b d x + a d\right )} \log \left (b x + a\right )^{2} + {\left (b d x + a d\right )} \log \left (d x + c\right )^{2} - 2 \, b c + 2 \, a d - 2 \, {\left (b d x + a d\right )} \log \left (b x + a\right ) + 2 \, {\left (b d x + a d - {\left (b d x + a d\right )} \log \left (b x + a\right )\right )} \log \left (d x + c\right )\right )} B n}{2 \, {\left (a b^{2} c^{2} g^{2} i - 2 \, a^{2} b c d g^{2} i + a^{3} d^{2} g^{2} i + {\left (b^{3} c^{2} g^{2} i - 2 \, a b^{2} c d g^{2} i + a^{2} b d^{2} g^{2} i\right )} x\right )}} - A {\left (\frac {1}{{\left (b^{2} c - a b d\right )} g^{2} i x + {\left (a b c - a^{2} d\right )} g^{2} i} + \frac {d \log \left (b x + a\right )}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} g^{2} i} - \frac {d \log \left (d x + c\right )}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} g^{2} i}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*((b*x+a)/(d*x+c))^n))/(b*g*x+a*g)^2/(d*i*x+c*i),x, algorithm="maxima")

[Out]

-B*(1/((b^2*c - a*b*d)*g^2*i*x + (a*b*c - a^2*d)*g^2*i) + d*log(b*x + a)/((b^2*c^2 - 2*a*b*c*d + a^2*d^2)*g^2*
i) - d*log(d*x + c)/((b^2*c^2 - 2*a*b*c*d + a^2*d^2)*g^2*i))*log(e*(b*x/(d*x + c) + a/(d*x + c))^n) + 1/2*((b*
d*x + a*d)*log(b*x + a)^2 + (b*d*x + a*d)*log(d*x + c)^2 - 2*b*c + 2*a*d - 2*(b*d*x + a*d)*log(b*x + a) + 2*(b
*d*x + a*d - (b*d*x + a*d)*log(b*x + a))*log(d*x + c))*B*n/(a*b^2*c^2*g^2*i - 2*a^2*b*c*d*g^2*i + a^3*d^2*g^2*
i + (b^3*c^2*g^2*i - 2*a*b^2*c*d*g^2*i + a^2*b*d^2*g^2*i)*x) - A*(1/((b^2*c - a*b*d)*g^2*i*x + (a*b*c - a^2*d)
*g^2*i) + d*log(b*x + a)/((b^2*c^2 - 2*a*b*c*d + a^2*d^2)*g^2*i) - d*log(d*x + c)/((b^2*c^2 - 2*a*b*c*d + a^2*
d^2)*g^2*i))

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mupad [B]  time = 6.08, size = 239, normalized size = 1.32 \[ \frac {A}{g^2\,i\,\left (a\,d-b\,c\right )\,\left (a+b\,x\right )}+\frac {B\,\ln \left (e\,{\left (\frac {a+b\,x}{c+d\,x}\right )}^n\right )}{g^2\,i\,\left (a\,d-b\,c\right )\,\left (a+b\,x\right )}+\frac {B\,n}{g^2\,i\,\left (a\,d-b\,c\right )\,\left (a+b\,x\right )}-\frac {B\,d\,{\ln \left (e\,{\left (\frac {a+b\,x}{c+d\,x}\right )}^n\right )}^2}{2\,g^2\,i\,n\,{\left (a\,d-b\,c\right )}^2}+\frac {A\,d\,\mathrm {atan}\left (\frac {a\,d\,1{}\mathrm {i}+b\,c\,1{}\mathrm {i}+b\,d\,x\,2{}\mathrm {i}}{a\,d-b\,c}\right )\,2{}\mathrm {i}}{g^2\,i\,{\left (a\,d-b\,c\right )}^2}+\frac {B\,d\,n\,\mathrm {atan}\left (\frac {a\,d\,1{}\mathrm {i}+b\,c\,1{}\mathrm {i}+b\,d\,x\,2{}\mathrm {i}}{a\,d-b\,c}\right )\,2{}\mathrm {i}}{g^2\,i\,{\left (a\,d-b\,c\right )}^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*log(e*((a + b*x)/(c + d*x))^n))/((a*g + b*g*x)^2*(c*i + d*i*x)),x)

[Out]

A/(g^2*i*(a*d - b*c)*(a + b*x)) + (B*log(e*((a + b*x)/(c + d*x))^n))/(g^2*i*(a*d - b*c)*(a + b*x)) + (A*d*atan
((a*d*1i + b*c*1i + b*d*x*2i)/(a*d - b*c))*2i)/(g^2*i*(a*d - b*c)^2) + (B*n)/(g^2*i*(a*d - b*c)*(a + b*x)) + (
B*d*n*atan((a*d*1i + b*c*1i + b*d*x*2i)/(a*d - b*c))*2i)/(g^2*i*(a*d - b*c)^2) - (B*d*log(e*((a + b*x)/(c + d*
x))^n)^2)/(2*g^2*i*n*(a*d - b*c)^2)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*ln(e*((b*x+a)/(d*x+c))**n))/(b*g*x+a*g)**2/(d*i*x+c*i),x)

[Out]

Timed out

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